Math, asked by MOHDARHAMSCC3A, 6 months ago

15. A man is 4 times as old as his son. After 16 years he will be only twice as old as his son.
Find their present ages.​

Answers

Answered by priyanshukumawat30
4

Answer:

let son age be x

so father age is 4x

After 16 years

x+16 and 4x+16

2(x+16)=4x+16

2x+32=4x+16

4x-2x = 32-16

2x = 16

x is 8

if son is 8 then father will be 4x

4×8=32

Answered by tejanadh2509
1
  • Answer:
  • At present :

  • At present :Son age = 8 years

At present :Son age = 8 yearsFather age = 32 years

  • Step-by-Step-Explaination

At present:

Age of son = x years

His Father age = 4x years

After 16 years:

Age of son = (x+16) years

Father age = (4x+16) years

According to the problem given,

Therefore,

At present :

Son age = x = 8 years

Father age = 4x=4×8 = 32 years

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