Question

15 acetic acid solution contains 20% acetic acid and remaining solution water find the present age of acetic acid in the new solution when 7 litre of dionized water mixed in the new solution

Answer 1

Therefore the acetic acid in new solution is=12.5%

Step-by-step explanation:

Given, 15 liter acetic acid solution contains 20 % acetic acid and remaining solution water.

The amount of acetic acid in 15 liter acetic acid solution is $=\frac{20}{100} \times 15$   liter

                                                                                                   = 3  liter

The amount of water in 15 units acetic acid solution is= (15-3)  liter

                                                                                         =12 liter

In the new solution 7 liter of deionized water mixed.

Therefore the total amount of water is = (12+7) liter =21 liter

Then total amount of acid solution is = (21+3) liter = 24  liter

The amount of acetic acid in the solution remains same.

Therefore the acetic acid in new solution is $=\frac{\textrm{amount of acid}}{\textrm{amount of solution}} \times 100 \%$

                                                                           $=\frac{3}{24}\times 100\%$

                                                                            =12.5%