Question

15. The difference between two selling prices of a jacket at profits 4% and 5% is 6. Find the (a) cost
price of the jacket (b) two selling prices of the jacket.
​

Answer 1

We are given that the difference between the two selling prices of a jacket at profits 4%4% and 5%5% is Rs. 6.

Let us assume that the cost of each jacket is Rs. x.

Now we will add the cost of each jacket with the profits of the first jacket cost to find the selling price of the first jacket, we get

⇒Selling price of first jacket=x+4/100×x

⇒Selling price of first jacket=x+x/25

⇒Selling price of first jacket=26x/25

Adding the cost of each jacket with the profits of the second jacket cost to find the selling price of the second jacket, we get

⇒Selling price of second jacket=x+5/100×x

⇒Selling price of second jacket=x+x/20

⇒Selling price of second jacket=21x/20

Since we are given that the difference between the selling price of the first jacket and the second jacket is Rs. 6, so we have

⇒21/20x−26/25x=6

⇒105x−104/100=6

⇒x/100=6

Multiplying the above equation by 100 on both sides, we get

⇒100×x/100=6×100

⇒x=600

Hence, the cost price of each jacket is Rs. 600.

Substituting the value of cost jacket in the selling price of the first jacket and second jacket, we get

⇒Selling price of first jacket=26/25×600

⇒Selling price of first jacket=Rs. 624

⇒Selling price of second jacket=21/20×600

⇒Selling price of second jacket=Rs. 630

Hence, the cost price of each jacket is Rs. 600 and the selling prices of the two jackets are Rs. 624 and Rs. 630 respectively.