Question

15x^2-10root6 x +10 =0
by quadratic formula !!

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Answer 1

Answer:

$5(3x {}^{2} - 2 \sqrt{6x + 2)} = 0 \\ 3x { }^{2} - 2 \sqrt{6x} + 2 = 0 \\ 3x {}^{2} - \sqrt{6x} - \sqrt{6x} + 2 = 0 \\ \sqrt{3x} ( \sqrt{3x} - \sqrt{2} ) - \sqrt{2} ( \sqrt{3x} - \sqrt{2} ) = 0 \\ (\sqrt{3x} - \sqrt{2} )( \sqrt{3x} - \sqrt{2}) = 0 \\ x = \frac{ \sqrt{2} }{ \sqrt{3 } }$