Question

15x^2-23x-28 by splitting the middle term​

Answer 1

Step-by-step explanation:

15x²-23x-28

=15x²-35x+12x-28

=5x(3x-7)+4(3x-7)

=(5x+4)(3x-7)

Answer 2

$\fbox{ \fbox{\bold{ \large{Answer :- \: }}}}$

$\implies \: x = \frac{ - \: 4}{5} \: \: \: \: or \: \: \: \: x = \frac{7}{3}$

$\fbox{ \fbox{ \bold{ \large{Given :- \: }}}}$

$\implies \: 15 {x}^{2} - 23x - 28 = 0$

$\fbox{ \fbox{ \bold{ \large{To \: Find :- \: }}}}$

$\implies \: x = \: ?$

$\fbox{ \fbox{ \bold{ \large{Solution :- \: }}}}$

$\implies \: 15 {x}^{2} - 23x - 28 = 0 \\ \\ \implies \: 15 {x}^{2} - 35x + 12x - 28 = 0 \\ \\ \implies \: 5x(3x - 7) + 4(3x - 7) = 0 \\ \\ \implies \: (5x + 4) \: (3x - 7) = 0 \\ \\ \implies \: x = \frac{ - \: 4}{5} \: \: \: \: or \: \: \: \: x = \frac{7}{3}$