15y-2(4y-1)=2(3y-1 ) give answer
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Answered by
31
Hey mate, here is your answer -:)
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![15y - 2(4y - 1) = 2(3y - 1) \\ \: \: \: \: \: \: 15y - 8y + 2 = 6y - 2 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 7y + 2 = 6y - 2 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 7y - 6y = - 2 - 2 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: y = - 4 15y - 2(4y - 1) = 2(3y - 1) \\ \: \: \: \: \: \: 15y - 8y + 2 = 6y - 2 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 7y + 2 = 6y - 2 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 7y - 6y = - 2 - 2 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: y = - 4](https://tex.z-dn.net/?f=15y+-+2%284y+-+1%29+%3D+2%283y+-+1%29+%5C%5C++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A+15y+-+8y+%2B+2+%3D+6y+-+2+%5C%5C++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++7y+%2B+2+%3D+6y+-+2+%5C%5C++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A+7y+-+6y+%3D++-+2+-+2+%5C%5C++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A+y+%3D++-+4)
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HOPE it helps to you!!!
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HOPE it helps to you!!!
nanudhull464:
hlo ji
Answered by
10
15y - 2(4y - 1) = 2(3y - 1 )
Distribute -2 and 2:
15y - 8y + 2 = 6y - 2
Combine like terms:
7y + 2 = 6y - 2
Subtract 6y from both sides:
y + 2 = -2
Subtract -2 from both sides:
y = -4
Answer: y = -4
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