Question

16. 2.2 dm3 of lead is to be
drawn into a cylindrical wire
0.50 cm in diameter. The length
of the wire is​

Answer 1

Let the length of the wire be 'h' cm

1 dm = 10 cm

Volume of metal = 2.2 dm³ = 2.2(10 cm)³

= 2.2*1000

Volume of metal = 2200 cm³

Let 'r' be the radius of the cylinder.

Given : Diameter = 0.25 cm  

So, r = 0.25/2  

r = 0.125 cm

Volume of metal in the wire = 2200 cm³

∴ πr²h = 2200 cm³

⇒ 22/7*(0.125)²*h = 2200

⇒ h = (2200*7)/22*0.015625

⇒ h = 15400/0.34375

h = 44800 cm

Or 44800/10  

Height = 4480 dm