Question

16(2p-3q)²-4(3q-2p) .factorise

Answer 1

given
16(2p-3q)²-4(3q-2p)

taking 2p-3q as common

2p-3q ((16×(2p-3q)+4(-1))

2p-3q (32p-48q-4)
take 4 as common
2p-3q .4. (8p-12q-1)



answer :- 4 • (2p - 3q) • (8p - 12q - 1)

Answer 2

Solution ●●●●
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$= 16( {2p - 3q})^{2} + 4(2p - 3q) \\ \\ = (2p - 3q) \: [\: 16(2p - 3q) + 4 ]\\ \\ = (2p - 3q)(32p - 48q + 4) \\ \\ = (2p - 3q) \: 4(8p - 12q + 1) \\ \\ = 4(2p - 3q)(8p - 12q + 1)$
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I hope it will help you