Question

16(5x-y)^2 - 9(3x-2)^2

Answer 1

Is the question complete ??
There should something equal to this like either 0 or any other number

Answer 2

$16 {(5x - y)}^{2} - 9 {(3x - 2)}^{2} \\ \\ = > [{4(5x - y)}]^{2} - [3 {(3x - 2)}]^{2} \\ \\ = > {(20x - 4y)}^{2} - {(9x - 6)}^{2} \\ \\ = > (20x - 4y + 9x - 6)(20x - 4y - 9x + 6) \\ \\ = > (29x - 4y - 6)(11x - 4y + 6) \\ \\ As \: we \: know \: that: \: {a}^{2} - {b}^{2} = (a + b)(a - b)$