Question

16 find the value of y if a)3y+12=27
b)3(y+12)=27
please answer fast help​

Answer 1

Answer:

Question :-

find the value of y if

Required Answer :-

Equation 1

$3y+12=27$

$3y = 27 - 12$

$3y = 15$

$y = \frac{15}{3}$

$y = \frac{ 1\cancel5}{\cancel3}$

$y = 5$

Equation 2

$3(y+12)=27$

$3 \times y + 3 \times 12 = 27$

$3y + 36 = 27$

$3y = 27 - 36$

$3y = - 9$

$y = \frac{ - 9}{3}$

$y = \frac{ - \cancel9}{ \cancel3}$

$y = - 3$

Answer 2

Answer:

ஃ y = 5

ஃ y = -3

Step-by-step explanation:

a) 3y + 12 = 27

3y = 27 - 12 = 15

3y = 15

$\sf y = \frac{15}{3} = 5$

y = 5

b) 3 ( y + 12 ) = 27

3y + ( 3 × 12 ) = 27

3y + 36 = 27

3y = 27 - 36

3y = -9

$\sf y = \frac{ - 9}{3} = - 3$

y = -3