Question

16. Points A (-3, -2), B (-6, a), C (-3, -4)
and D(0, -1) are the vertices of quadri-
lateral ABCD; find a if 'a' is negative and
AB = CD.​

Answer 1

Given :-

----> Four vertices of a parallelogram,

• A(-3,-2)
• B(-6,a)
• C(-3,-4)
• D(0,-1)

----> Value of 'a' is negative.

----> AB = CD

To find :-

Value of a.

Solution :-

Midpoint formula = ( x1+x2/2 , y1+y2/2 )

Now,

AB = CD

---> ( -3+(-6)/2 , -2+a/2 ) = ( -3+0/2 , -4+(-1)/2 )

---> ( -3-6/2 , -2+a/2 ) = ( -3+0/2 , -4-1/2 )

equating y coordinates,

---> -2+a/2 = -4-1/2

---> -2+a = -4-1

---> -2+a = -5

---> a = -5+2

---> a = -3

____________________________

•°• a = -3

Answer 2

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