Question

16. Steam at 100°C is passed into 20 g of water at
10°C. When water acquires a temperature of 80°C.
the mass of water present will be:
[Take specific heat of water = 1 cal g-1°C-1 and
latent heat of steam = 540 cal g-'] [AIPMT-2014]
(1) 24 g
(2) 31.5 g
(3) 42.5 g
(4) 22.5 g

Answer 1

Hlew,

Here's your answer...

Option 4 is correct.

Thanks.

Sorry baby 'wink'