cot π/8 - tan π/8=2 prove rhat
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Hlew,
Here's your answer...
Your answer is in the attachment below.
Thanks.
Sorry baby 'wink'
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Answer:
Cot( x/2)=cos(x/2) / sin(x/2)
= sqr(1+cosx)/sqr(1-cosx)
=sinx/(1-cosx)
So cot (pi/8)= sin (pi/4) / [1-cos(pi/4)]
=(sqr2)/2 / [1-(sqr2)/2]
=sqr2/(2-sqr2)
= Sqr2(2+sqr2)/2
= (2sqr2+2)/2
= sqr2+1
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