16.
The order of the recurrence equation dn - 3dn-2 + dn-4 = 1 is:
2
A) First order
B) Second order
C) Third order
D) Fourth order
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Answer:
the recurrence equation dn-3db-2 +dn-4=1 is
Step-by-step explanation:
1) dn-3db-2 +dn-4=1
2)1=-4dn+2-db3-dn
4dn+2-db3=-dn
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