Math, asked by rxtanmay135, 1 month ago

16.
The order of the recurrence equation dn - 3dn-2 + dn-4 = 1 is:
2
A) First order
B) Second order
C) Third order
D) Fourth order​

Answers

Answered by Anshusingh00
0

Answer:

the recurrence equation dn-3db-2 +dn-4=1 is

Step-by-step explanation:

1) dn-3db-2 +dn-4=1

2)1=-4dn+2-db3-dn

4dn+2-db3=-dn

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