Math, asked by sacredian, 1 month ago

prove that each of the following numbers is irrational
 \sqrt{5 - 2}

Answers

Answered by HandsomeBoii
0

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Answered by CopyThat
7

Answer :-

\bold{\sqrt{5}-2} is irrational number.

Step-by-step explanation :-

Given :

\bold{\sqrt{5}-2}

To find :

To prove that \bold{\sqrt{5}-2} is irrational.

Solution :

Let \bold{\sqrt{5}-2} be a rational number.

\rightarrow \bold{\sqrt{(5-2})^2}=\bold{x^2}

\rightarrow \bold{5+4-2\times2\times\sqrt{5} }=\bold{x^2}

\rightarrow \bold {9-x^2}=\bold{4\sqrt{5}}

\rightarrow \bold{\sqrt{5}}=\bold{\frac{9-x^2}{4}}

Here, we have x , x², 9 - x², 9 - x²/4 as rational numbers.

But √2 is an irrational number.

So,  x , x², 9 - x², 9 - x²/4 become irrational.

Our assumption is wrong.

\bold{\sqrt{5}-2} is irrational number.

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