16.
Two trees, A and B are on the same side of a river. From a point C in the river the
distance of the trees A and B is 250 m and 300 m, respectively. If the angle C is
45°, find the distance between the trees (use 2 = 1.44). (Ans. 215.5 m)
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- Question⇒ Two trees, A and B are on the same side of a river. From a point C in the river the distance of the trees A and B is 250 m and 300 m, respectively. If the angle C is 45°, find the distance between the trees (use 2 = 1.44).
Step-by-step explanation:
- In ΔABC
- ∠C = 45
- AC = 250 m
- BC = 300m
- by applying the cosine rule
- a²= b² + c² - 2bc cos A
- so,
- AB² = AC² + BC² - 2 AC BC cos C
- = 250² + 300² - 2 x 250 x 300 x cos 45
- AB²= 46433.98
- taking under root
- AB = 215.5 m
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