Question

the no of real solutions of the equation sinx=x^2+3x+4 is​

Answer 1

Answer:

no real Solution

Step-by-step explanation:

the no of real solutions of the equation sinx=x^2+3x+4 is​

-1 ≤ Sinx  ≤ 1

x²+3x+4 = Sinx

x²+3x+4 - Sinx = 0

for real solution  D > 0

3² - 4(4 - Sinx) > 0

=> 9 - 16 + 4Sinx > 0

=> 4Sinx > 7

=> Sinx > 7/4

While  -1 ≤ Sinx  ≤ 1

so Sinx ≠ 7/4 => no real Solution