16x+y=14, 12x-y=12 by substitution method
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16x+y=14...................(1)
12x-y=12....................(2)
from eq 2 we get
12x-y=12
12x=12+y
x=12+y/12.........(3)
putting the value of eq 3 on eq 1 we get
16x+y=14
16(12+y/12)+y=14
find this and then u will find the value of y
put the value of y in eq 3
then u will get both x and y.
12x-y=12....................(2)
from eq 2 we get
12x-y=12
12x=12+y
x=12+y/12.........(3)
putting the value of eq 3 on eq 1 we get
16x+y=14
16(12+y/12)+y=14
find this and then u will find the value of y
put the value of y in eq 3
then u will get both x and y.
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ur ans is in this attachment
I hope it's helpful ☺️☺️✅
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