Question

17.0 gm of silver nitrate was allowed to react with sodium chloride and resulted in the

formation of 14.35 gm of silver chloride and 8.5 gm of sodium nitrate.What is the mass of​

Answer 1

Answer:

AgNO3 + NaCl - - - >AgCl + NaNO3

17g. x g 14.5 g. 8.5

Using conservation of mass,

17+x=14.35+8.5=22.85 g

x=5.85 g answer.

Hope this will help you

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