Question

17.


CuO-H. Cu - H2O is a balanced equation. causing reduction of CuO. What volume of H2 at
STP is required to reduce 7.95 gm of CuO to give Cu and H2O?
(Atomic weight of Cu= 63.5 u and Atomic weight ofO=16 u
1)224 lit
2)22.4 lit
3)2.24 lit
4)0.224 lit

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Answer 1

Answer:

2.24

Explanation:

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Answer 2

At STP 2.24L $H_2$ is required to reduce 7.95 gm of CuO to give Cu and $H_2O$.

Given:

$CuO+ H_2$ → $Cu+ H_2O$

The weight of CuO is 7.95g.

To Find:

The volume  $H_2$ is required to reduce 7.95 gm of CuO.

Solution:

The molecular weight of CuO is = (63.5 + 16)g = 79.5g.

At STP,

79.5 g CuO is reduced by 22.4L H2.

Therefore, 7.95 g CuO is reduced by 2.24L H2.

Hence, at STP 2.24L $H_2$ is required to reduce 7.95 gm of CuO to give Cu and $H_2O$.

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