Question

17. In a game period the teacher of Meerut Public firstly the teacher draws a geometrical figure on the ground, which is shown below. School decided to play the puzzle game. For this game, is a transversal line. While drawing this figure, the teacher has no two of the angles as shown in the figure. In this game, the and asks them to stand at specified points. Vicky stands at Here line I is parallel to m and q protractor for measuring angles, but he marks teacher invites two students Vicky and Vishal point A and Vishal stands at point B. Then, answer the following questions, which are based on above data. i) ii) iv) v) Measure of angle ABD is a) 70° Measure of angle theta 1 is a) 70 degrees b) 80 degrees b) 80 degrees Measure of angle theta 2 is a) 70 degrees Measure of angle theta 3 is a) 70 degrees b) 80 degrees b) 80 degrees Measure of angle GAD is a) 100° b) 90 degrees c) 90 degrees c) 90 degrees c) 90 degrees c) 90 degrees c) 110 degrees d) 100 degrees d) 100 degrees d) 100 degrees 100 degrees d) d) 120 degrees ​

Answer 1

Answer:

i- 70⁰

ii-80⁰

iii-70⁰

iv80⁰

v-100⁰

Step-by-step explanation:

I hope it helps it comes in exam

Answer 2

Solution :-

(i)

In the given figure,

→ ∠ABD + ∠DBE = 180° { Linear pair }

→ ∠ABD + 110° = 180°

→ ∠ABD = 180° - 110°

→ ∠ABD = 70° (a)

(ii)

→ ∠DAB + ∠BDA = ∠DBE { Exterior angle of a ∆ is equal to sum of opposite interior angles }

→ θ1 + 30° = 110°

→ θ1 = 110° - 30°

→ θ1 = 80° (b)

(iii)

Since I || m ,

→ θ2 = ∠ABD { Alternate interior angles }

→ θ2 = 70° (b)

(iv)

since A - D - H is a straight line .

→ ∠ADB + θ2 + θ3 = 180°

→ 30° + 70° + θ3 = 180°

→ 100° + θ3 = 180°

→ θ3 = 180° - 100°

→ θ3 = 80° (c)

(iv)

→ ∠GAD = ∠ABD + ∠BDA { Exterior angle of a ∆ is equal to sum of opposite interior angles }

→ ∠GAD = 70° + 30°

→ ∠GAD = 100° (a)

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