Math, asked by bhuvibhuva247, 4 months ago

17. Savita has a square plot of side 60m
She wants to construct a house of
dimensions 40m x 30m in the middle of
the plot and develop a lawat
remaining area. Find the total cost of
developing the lawn around the house at
the rate of Rs. 50 per square metre​

Answers

Answered by msanonymous
1

Answer:

The given plot is a square with side 60m

Area of the plot = side²

= 60²

= 3600m²

The constructed portion is a rectangle having length = 40m and breadth = 30m

Area of the constructed portion = 40 x 30

= 1200 m²

Now, area of the lawn =

[total plot area] - [total constructed area]

= (3600 - 1200)m²

= 2400 m²

cost of developing the lawn = Rs. 50 x 2400

= Rs. 120,000

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Answered by anujsharma44181
0

Step-by-step explanation:

the side of a square plot (a) = 60 m

And the demensions of house which is in the middle of plot = 40 m × 30 m

So, the area of lawn = the area of square - the area of house

the area of lawn = a^ - l×b

= 60×60 - 40 ×30

= 3600 - 1200

= 2400 m^

so, the total cost of developing the lawn around the house at the rate of Rs. 50 per square meter

= area of lawn × 50

= 2400 × 50

= Rs.120000

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