Question

(18)
Q.1
Ram sold a motorcycle for 70000 at 25% profit. For what price should be sell a motorcycle to gain 30% profit?
Ans
X 1. 72.900
X 2 72,600
3. 372,800
x 4.372,700
Question
Statu
Chosen Optio​

Answer 1

Answer:

3 rd option = 72,800

Step-by-step explanation:

Let c.p of motor cycle = 100

then 25% of 100 = 25

S.p of motor cycle = 125.

but S.p is 70000

so we use Arrow method..

100 -----> 125

x. ------> 70000

So c.p of motor cycle =( 70000÷125) × 100

= 56,000

then he wants to 30% of profit so=

56000×30% = 16,800

so total Amount = 56000+16800= 72,800.

Answer 2

➤ Given :-

Selling price of a motorcycle :- ₹70000

Profit percentage :- 25%

$\:$

➤ To Find :-

The selling price if sold at profit 30%.

$\:$

★ How to do :-

Here, we are given with the selling price and the profit percentage obtained to a motorcycle. We are asked to find the selling price of the same motorcycle if it's sold at a profit of 30%. So, first we should find the cost price of the motorcycle by using the information given in the first statement. The suitable formula is given while solving the problem. Later, we can find the selling price of second statement by using the cost price and the new profit percentage. So, let's solve!!

$\:$

➤ Solution :-

Let's find the cost price of the motorcycle.

Cost price of motorcycle :-

${\tt \leadsto \underline{\boxed{\tt \dfrac{100}{(100 + Gain \bf\%)} \times SP}}}$

Substitute the given values.

${\tt \leadsto \dfrac{100}{(100 + 25)} \times 70000}$

First, add the numbers in the denominators.

${\tt \leadsto \dfrac{100}{125} \times 70000}$

Write the fraction in the lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{100}{125} \times 70000 = \dfrac{4}{5} \times 70000}$

Write the denominator and the whole number in lowest form by cancellation method.

${\tt \leadsto \dfrac{4}{\cancel{5}} \times \cancel{70000} = \dfrac{4}{1} \times 14000}$

Multiply the remaining numbers.

${\tt \leadsto 4 \times 14000 = \underline{56000}}$

$\:$

Now, let's find the selling price if it's sold at a profit of 30%.

Selling price of the motorcycle :-

${\tt \leadsto \underline{\boxed{\tt \dfrac{(100 + Gain \bf\%)}{100} \times CP}}}$

Substitute the given values.

${\tt \leadsto \dfrac{(100 + 30)}{100} \times 56000}$

First, add the numbers in the numerator.

${\tt \leadsto \dfrac{130}{100} \times 56000}$

Write the fraction in the lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{130}{100} \times 56000 = \dfrac{13}{10} \times 56000}$

Write the denominator and the whole number in lowest form by cancellation method.

${\tt \leadsto \dfrac{13}{\cancel{10}} \times \cancel{56000} = \dfrac{13}{1} \times 5600}$

Multiply the remaining numbers.

${\tt \leadsto 13 \times 5600 = \pink{\underline{\boxed{\tt Rs \: \: 72800}}}}$

$\Huge\therefore$ The selling price of the motorcycle is ₹72800.

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$\dashrightarrow$ Some related formulas :-

$\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{Gain = S.P - C.P} \\ \\ \bigstar \:\sf{Loss = C.P - S.P} \\ \\ \bigstar \: \sf{Gain \: \% = \Bigg( \dfrac{Gain}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{loss \: \% = \Bigg( \dfrac{loss}{C.P} \times 100 \Bigg)\%} \\ \\\bigstar \: \sf{S.P = \dfrac{100-loss\%}{100} \times C.P} \\ \\ \bigstar \: \sf{C.P =\dfrac{100}{100-loss\%} \times S.P}\end{array}}$