Question

1800
a force (4.01 +3.07) 10-N on a particle having a
charge 10' C and moving in the x-y plane. Find the
4x100 = 4v, x10-12
Problem-11:A magnetic field of (4.0x 10- )exer
a )*°N
velocity of the particle.
Solation: Magnetic force m = (4.0i +3.0)x10-ton
Let velocity of the particle in x-y plane be
, v= vưitv,j
Then from the relation Fn = 9(vxB)
we have (4.0î+3.09)x10-10
10*|{v,i+v,j] (4x10')]
=(4v, x10-12; -4v, x10-123)
comparing the coefficient of i and j we have,
: Vy
v=-75 m/s
= 10%m/s = 100m/s and 3.0x10-10 = -4v, *10-12
.: =-75 +100
V.​

Answer 1

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