Question

19). A train is travelling at a speed of 90kmph. Brakes are applied
so as to produce a uniform acceleration of -0.5m/s2. Find how far
the train will go before it is brought to rest.​

Answer 1

whether the answer is 25meter?

Answer 2

Answer:

Therefore, the train will go 635m before it is brought to rest.

Step-by-step explanation:

The initial speed is "u"=90km per hour=90{\times}\frac{5}{18}=25ms^{-1}. Since, the breaks applied, therefore v=0.

Now, using the third equation of the motion,

v^{2}=u^{2}+2as

0=(25)^{2}+2(-0.5)(s)

0=625-s

s=625m

Therefore, the train will go 635m before it is brought to rest.