Question

19.
A wire is bent in the form of circle of radius 2m. Resistance
per unit length of wire is 1/1 12/m. Battery of 6V is
connected between A & B. AOB = 90°. Find the current
through the battery
[GUJCET 2014]
Oo...
B
(a) 8A
(b) 4A
(c) 3A
(d) 9A
6 V​

Answer 1

Answer:

A is right answer

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Answer 2

Answer:

The correct option (B) 4A Explanation: Length of wire = 2πr = 2π × 4 = 8π {(Resistance)/(length)} = (1/π) ∴ Total resistance of wire = 8π × (1/π) = 8Ω as circle can be divided in two portions. R1 is resistance of (1/4)th portion of wire & R2 is resistance of (3/4)th portion ∴ Resistance of circle = R1 || R2 = 2 || 6 ---- [R1 = (1/4) × 8Ω, R2 = (3/4) × 8Ω] R = {(2 × 6)/(2 + 6)} = (12/6) = (3/2)Ω ∴ I = (6/R) = {6/(3/2)} = 4ARead more on Sarthaks.com - https://www.sarthaks.com/346156/wire-bent-the-form-circle-radius-resistance-per-unit-length-wire-battery-connected-between

Explanation:

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