Math, asked by yashwanth682, 11 months ago

(cosecA-sinA)(secA-cosA)=1\cotA+tanA​

Answers

Answered by Superglactus
1

Answer:

1

Step-by-step explanation:

(cosecA-sinA) (secA-cosA) = 1/(tanA+cotA).

L.H.S.

=(cosecA-sinA) (secA-cosA).

=(1/sinA-sinA)(1/cosA-cosA).

=(1-sin^2A) (1-cos^2A)/sinA.cosA.

=cos^2A.sin^2A/sinA.còsA.

=sinA.cosA/1.

=sinA.cosA/(sin^2A+cos^2A).

On dividing above and below by sinA.cosA.

=(sinA.cosA/sinA.cosA)/(sin^2A/sinA.cosA+cos^2A/sinA.cosA).

= 1/(tanA+cotA).

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