Question

19. Find the smallest number, which is when divided by 14,
21, 28 and 35 leaves remainder 6 in each case.​

Answer 1

Answer:

The first smallest number of 14 is 14×1 =14

so we leave the remainder 6?

14 +6 = 20

its number are not registred

next 14×2 = 28

28+6 =34

next 14 × 3 = 42

42+6=48

the question i think wrong