Question

19. How many O atoms are in 1.25 mol of SO2



?

Answer 1

No.of oxygen atoms in 1 mol of SO2 = 2 × 6.02×10^23

No. of oxygen atoms in 1.25 mol of SO2 = 1.25×2×6.02×10^23 = 15.05 × 10^23 atoms

Answer 2

As it is already known, 1 mole of any substance contains 6.023×10^23 atoms.

In Sulfur dioxide( SO2 ) -

1 mole of SO2 contains one sulfur and two oxygen molecules.

So, 1 mole of S02 contains - 2(6.023×10^23) atoms

= 12.046×10^23 atoms

So, the number of oxygen atoms present in 1.25 moles of SO2 are= 1.25( 12.046× 10^23)

= 15.06× 10^23 atoms

Answer: The number of oxygen atoms present in 1.25 moles of sulfur dioxide(SO2) is 15.06× 10^23.