Question

1913 XI
A coil of wire has an area of 600 sq.cm and has 500 turns. If it carries 1.5 A current,
find its magnetic dipole moment
1) 5 Am
4) 45 Am
2) 15 Am
3) 30 Am?​

Answer 1

Answer:

45Am

Explanation:

see friend,

magnetic dipole =NIA

=500*1.5*0.06

=45Am

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Answer 2

The magnetic dipole moment of coil of wire is 45 Am². hence, option (4) is correct choice.

A coil of wire has an area of 600 sq.cm and has 500 turns. If it carries 1.5 A current.

We have to find the magnetic dipole moment.

The magnetic dipole moment of a coil of wire is given by, M = ANi

Where,

• A is cross sectional area of coil of wire.
• N is number of turns
• i is current through the wire.

Here, A = 600 cm² = 600 × 10⁻⁴ m² = 0.06 m² , N = 500 turns  and i = 1.5A

∴ M = 0.06 × 500 × 1.5 = 45 Am²

Therefore the magnetic dipole moment of coil of wire is 45 Am². hence, option (4) is correct choice.