Math, asked by narendrarathod86, 1 year ago

2(1)/(2)+(-3(1)/(2))+(-2(1)/(3))+(2(1)/(9))

Please explain completely step by step.

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Answers

Answered by TooFree
6

 \textbf {Hey there, here is the solution.}

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I believe the question meant to say:

 2\dfrac{1}{2} + \bigg(-3 \dfrac{1}{2} \bigg) + \bigg(-2\dfrac{1}{3}   \bigg) + \bigg( 2\dfrac{1}{9} \bigg)

Lets start by working on the first two terms:

 = 2\dfrac{1}{2}  -3 \dfrac{1}{2} + \bigg(-2\dfrac{1}{3}   \bigg) + \bigg( 2\dfrac{1}{9} \bigg)

 = -1 + \bigg(-2\dfrac{1}{3}   \bigg) + \bigg( 2\dfrac{1}{9} \bigg)

Now we work on the next two terms:

 = -1 -2\dfrac{1}{3}   + \bigg( 2\dfrac{1}{9} \bigg)

 =  -3\dfrac{1}{3}   + \bigg( 2\dfrac{1}{9} \bigg)

And finally the last the two terms:

 =  -3\dfrac{1}{3}   + 2\dfrac{1}{9}

 =  -3\dfrac{3}{9}   + 2\dfrac{1}{9}

 =  -1\dfrac{2}{9}

or write it as in improper fraction:

 =  -\dfrac{11}{9}

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 \textbf {Cheers}


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