Question

(2^-1-3^-1)+(6^-1-8^-8)​

Answer 1

Answer:

$( {2}^{ - 1} - {3}^{ - 1}) +( {6}^{ - 1} - {8}^{ - 8}) \\ \\since \: \: {8}^{ - 8} \approx0 \\ \\ \approx \frac{1}{2} - \frac{1}{3} + \frac{1}{6} \\ \\ = \frac{3 - 2 + 1}{6} \\ \\ = \frac{1}{3}$

Answer 2

$\huge{\boxed{\boxed{\red{\ulcorner{\mid{\overline{\underline{\bf{Answer:-}}}}}\mid}}}}$

$\huge \red \rightarrow \huge\red{ {3}^{ - 1} }$

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