Question

2.2 g of a compound of phosphrous and sulphur has 1.24 g of P in it its emperical formula is....

Answer 1

Atomic weight of phosphorous = 31 and sulphur = 32

Given, weight of phosphorous = 1.24 and sulphur = 2.2 - 1.24 = 0.96


Empirical formula = (1.24/31) : (0.96/32)

                              = 4:3


So the formula is p4s3.


Hope this helps!

Answer 2

hope it will help you