Math, asked by ayra8, 11 months ago

[(2/3)^-2]^3×(3/2)^2n=(4/9)^2​

Answers

Answered by Anonymous
16

Step-by-step explanation:

[(2/3)^-2]^3×(3/2)^2n=(4/9)^2

[(3/2)^2]^3×(3/2)^2n=(2/3)^4

[(3/2)]^(6+2n)=(3/2)^-4

Compairing both sides.....

(6+2n)=-4

2n=-4-6

n=-10/2

n=-5

Hope this helps you

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