Math, asked by Priyanshu7ms, 2 months ago

(2-√3-2-√3)^3 How to solve this. Pls explain​

Answers

Answered by srivarshinit
1

(2-√3-2-√3)^3

= (2^3-√3^3-2^3-√3^3)

= (8-3√3-8-3√3)

= [0-3-3(√3)]

= (-6√3)

Similar questions