Question

2/3, 8/9,64/81 और 10/27 का महत्तम समापवर्त्य होगा-
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Answer 1

Answer:

$HCF( \frac{2}{3} \frac{8}{9} \frac{64}{81} \frac{10}{27} ) = \frac{HCF(2 \: 8 \: 64 \: 10)}{LCM(3 \: 9 \: 81 \: 27)} = \frac{2}{81} \\ \\ \\ Now \\ \: \: HCF \: of \: \frac{2}{3} = \frac{2}{3} \div \frac{2}{81} = 27 \\ \\ \: HCF \: of \: \frac{8}{9} = \frac{8}{9} \div \frac{2}{81} = 36 \\ \\ \: HCF \: of \: \frac{64}{81} = \frac{64}{81} \div \frac{2}{81} = 32 \\ \\ \: HCF \: of \: \frac{10}{27} = \frac{10}{27} \div \frac{2}{81} = 15$

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