Question

2/3rd of the balls in a bag are blue, the rest are pink. if 5/9th of the blue balls and 7/8th of the pink balls are defective, find the total number of balls in the bag given that the number of non defective balls is 146?

Answer 1

Not to be confused with- Calcification

Authorities differ on the meaning of calcination (also referred to as calcining). The IUPAC defines it as 'heating to high temperatures in air or oxygen'.[1] However, calcination is also used to mean a thermal treatment process in the absence or limited supply of air or oxygen applied to ores and other solid materials to bring about a thermal decomposition. A calciner is a steel cylinder that rotates inside a heated furnace and performs indirect high-temperature processing (550–1150 °C, or 1000–2100 °F) within a controlled atmosphere.[2]

Answer 2

Answer:

The total balls are 432.

Step-by-step explanation:

Let, x be the total numbers of ball in the bag,

Since, total blue balls = 2/3rd of total balls = $\frac{2}{3}x$

⇒ Total pink balls = 1/3rd of total balls = $\frac{1}{3}x$

Now, the defective blue balls = 5/9th of the blue balls,

⇒ The non defective blue balls = 4/9th of the blue balls = $\frac{8}{27}x$

Also, the defective pink balls = 7/8th of the blue balls,

⇒ The non defective blue balls = 1/8th of the blue balls = $\frac{1}{24}x$

Total non defective balls

$=\frac{8}{27}x+\frac{1}{24}x$

= $\frac{64x+9x}{216}$

= $\frac{73x}{216}$

According to the question,

$\frac{73x}{216}=146\implies x = 432$