Question

2.5
using the properties of Pythagoras and solves practical sums based on it.
Solve the following.
1. In A POR. ZP is right angle. If PQ 10 cm and PR 24 cm. Find QR.
trois broken height of 4m from the ground. Its top touches the ground at​

Answer 1

Step-by-step explanation:

In angle PQR,

PQ=10cm

PR=24cm

we need to find QR,

In angle PQR,

PR=base

PQ=height

QR=hypotenuse

we use pythagoras therom to find QR

( PR)²+(PQ)²=(QR)²

(24)²+(10)²=(QR)²

576+100=(QR)²

676=(QR)²

√676=QR

26=QR

Then the answer is QR = 26cm.

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