2х + 7y = 39
3х + 5 = 31
solve using elimination by substitution
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Answered by
2
Step-by-step explanation:
given,
2x +7y= 39...(i)
3x+5y=31....(ii)
now considering i
2x+7y=39
2x=39-7y
x=39/2 -7/2y.....(iii)
returning the value of x in ii
3[(39/2)-(7/2)y]+5y=31
(117/2)-(21/2)y+5y=31
(117/2)-31=(21/2)y-5y
55/2=(11/2)y
cancelling 2 both side
55=11y
y=55/11=5
from iii,
x=(39/2)-(7/2)y
x=(39/2)-(7/2)5
x=(39-35)/2
x=4/2=2
so your answer is x=2,y=5
hope u understand,
with regards,
anmol
Answered by
0
Answer:
By substitution method
Step-by-step explanation:
Hope it helps....
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