Question

2.82 g of glucose is dissolved in 30 g of water. Calculate the mole fraction of glucose and water.


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Answer 1

We know that,

The weight of glucose=2.82g

Also,

no. of moles of glucose=n2=1802.82=0.01567

no. of moles of N2O=n1=1830=1.667

Molality=n1n2×m.wtofsolvent1000

=1.6670.01567×181000=0.5222molal

We have moles of glucose (x2)=0.01567

moles of H2O(x1)=1.667

So, mole fraction of glucose

x2=n1+n2n2=(1.667+0.01567)0.0157=0.01567

mole fraction of H2O=x1

x1=1−x2=1=0.0093x1=0.9907

THE ANSWER IS 0.9907

Answer 2

Answer:

We know that,

The weight of glucose=2.82g

Also,

no. of moles of glucose=n2=1802.82=0.01567

no. of moles of N2O=n1=1830=1.667

Molality=n1n2×m.wtofsolvent1000

=1.6670.01567×181000=0.5222molal

We have moles of glucose (x2)=0.01567

moles of H2O(x1)=1.667

So, mole fraction of glucose

x2=n1+n2n2=(1.667+0.01567)0.0157=0.01567

mole fraction of H2O=x1

x1=1−x2=1=0.0093x1=0.9907

THE ANSWER IS 0.9907