Question

2.9 g of a gas at 95 degree C occupied the same volume as 0.184g of dihydrogen at 17 degree C at same pressure. What is the molar mass of the gas?

Answer 1

Hi

Here is your answer,

pV=nRT

Unknown Gas                  Hydrogen gas 
                                         p₂V₂=m₂RT₂/M₂
p₁V₁=m₁RT₁/M₁

p₁V₁=p₂V₂

Hence, m₁RT₁/M₁

2.9 g×R×368K/M₁ = 0.184g × R × 290 K/2 g mol⁻1

Molar mass of unknown gas, M₁ = 2.9 g × 368 K × 2 g mol⁻ 1/0.184 g × 290 K = 40 g mol⁻1


Hope it helps you !

Answer 2

Explanation:

attachment will help you to solve