Question

2. A bucket contains 3 red, 4 blue, 6 green,
7 yellow and 5 orange balls. Find the
mentioned probabilities
a. P (a red ball)
b. P (one red or one blue ball)
c. P (one green ball)
d. P (1 orange ball)
e. P (1 blue ball)
f. P (7 yellow balls)
g. P (a black ball) =
h. P (6 green balls)​

Answer 1

Answer:

a) 3/25

b)2/25

c)1/25

d)1/25

e)1/25

f)7/25

g)0

h)6/25

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