Question

2 A container consists of o, gas at 4 atm pressure and 400 K. If the volume of the container is 8.21 litre then calculate number of oxygen atoms present in the container ?​

Answer 1

Answer:

1.205 x10^24 atoms

Explanation:

First we have to calculate the volume of the gas at STP.

P°V°/T°=PV/T

Therefore V°= P V/T x (T°/P°)

V°= 4 x8.21/400 x(273/1)

=22.41 liters.

At STP 22.4 liters contains= 6.022 x 10^23 molecules = 6.022 x 2 x 10^23 atoms. So22.41 liters contains

=6.022 x2 x10^23 x22.41/22.4

= 1.205 x10^24 atoms

Answer 2

hope it will work for you bro.