Question

2 con B) Solve the following word [4] problems. Cany 2] J What is the maximum length of equal pieces that can be cut from two length of wire of 74cm and 92cm with a piece of remaining of each? 2​

Answer 1

Answer:

18 cm

Step-by-step explanation:

After cutting length of equal pieces from each of the wires, a piece of 2 cm is remaining of each.

Therefore, the equal pieces will be cut from wires of length,

74 - 2 = 72 cm

and

92 - 2 = 90 cm

(2). Now, we will calculate the H.C.F. of 72 cm and 90 cm by using the prime factorisation method.

Factors of 72 & 90:

72 = 2 × 2 × 2 × 3 × 3

90 = 2 × 3 × 3 × 5

H.C.F.:

H.C.F. of 72 & 90 = 2 × 3 × 3 = 18

Thus, the maximum length each of the equal pieces that can be cut from two lengths of wire of 74 cm and 92 cm with a piece of 2 cm remaining of each is 18 cm.

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