Question

2. Construct ∆PQR such tat PQ = 9.5 cm, PR = 8.5cm and QR = 9.8 cm.
i. Measure and write down the size of the angle facing the shortest side.
ii. Construct the perpendicular bisector of QR such that it cuts PQ.
iii. Measure and write down the length of QT such that T is the point where the
perpendicular bisector of QR cuts PQ.

Answer 1

Given : PQ = 9.5 cm, PR = 8.5cm and QR = 9.8 cm.

To find : Construct ∆PQR & perpendicular bisector of QR

Solution:

Step 1 : Draw a line segment PQ = 9.8 cm

Step 2 : using compass taking width = 8.5 cm and taking P as center draw an arc .

Step 3 : using compass taking width = 9.8 cm and taking Q as center draw an arc such that it intersct arc drawn in step 2 at R

Step 4 : join PR

Step 5 : join QR

∆PQR is constructed

Angle bisector of QR

Step 1 : Taking compass width slightly less than QR  & taking Q as center draw arcs on both sids of QR

Step 2 : Keeping compass width same as in previous step  and taking R as center , draw arcs such that it intersects arc drawn in previous step at A & B

Step 3 : join AB & extend it to cut PQ at T

AB is perpendicular Bisector of QR

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