2 cubes each of volume 64 cm3 are joined end to end find the surface area of the resulting cuboid
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Solution:
Given:
=> Volume of each cube = 64 cm²
=> Total volume of the two cubes = 2 × 64 cm² = 128 cm²
To Find:
=> Total surface area of resulting cuboid.
Formula used:
=> Total surface are of cuboid = 2(LB + BH + HL)
So,
Let the edge of each cube = x
=> x³ = 64
=> x = 4
Now, length of the resulting cuboid, L = 2x cm
Breadth of the resulting cuboid, B = x cm
Height of the resulting cuboid, H = x cm
Now,
Total surface are of cuboid = 2(LB + BH + HL)
=> 2[(2x × x) + (x × x) + (x × 2x)]
=> 2[(2 × 4 × 4) + (4 × 4) + (4 × 2 × 4)]
=> 2[32 + 16 + 32]
=> 2[80]
=> 160 cm²
So, the Total surface area of resulting cuboid = 160 cm²
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