2.
Expand ( a +1/1 )³
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4a^2+3a+1
Explanation:
( a +1/1 )³
we know that (a+b)^3=a^2+b^2+3ab(a+b)
so take 'a' as a and '1/1' as b
then-
( a +1/1 )³
=(a)^2+(1/1)^2+3×a×1/1(a+1/1)
=a^2+1+3a(a+1/1)
=a^2+1+3a^2+3a
=4a^2+3a+1 (ans)
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