Question

2. Find the angles of a triangle if sum of two angles of a triangle is 80° and their difference is
20°​

Answer 1

Answer:

∠A= 50°    ,∠B= 30°   ,∠C= 100°  .

Step-by-step explanation:

∠A+∠B=80°...........1

∠A-∠B=20.°...................2

SUM  EQN 1 AND EQN 2

∠A+∠B+∠A-∠B=80°+20°

2∠A=100°

∠A=50°

SUB ∠A=50° IN EQN 2

50°-∠B=20°

∠B=30°

SUM OF ALL ANGLES IN TRIANGLE IS 180°

∠A+∠B+∠C-=180°

50+30+∠C=180°

∠C=100°