Math, asked by pawansingh6589, 11 months ago

2. Find the base of a triangle whose area is 0.48 dm2 and altitude 8cm
3.Find the area of a right triangle whose hypotenuse is 13 cm and one side is 5 cm.​

Answers

Answered by Abhishekmohanta0338
5

Answer:

2.Base=0.12cm

3.Area of triangle=30cm

Step-by-step explanation:

to find the base

put the formula of area of a triangle

=1/2×base ×height

height is given=8cm

area is given=0.48cm

Now,

1/2×base ×height=Area of a triangle

=) 1/2×b×8=0.48

=)4×b=0.48

=)b=0.48/4

=)b=0.12

Hence,the base is 0.12

(3). Area of the right angle triangle

Given data,

hypotenuse side =13cm

let us consider the other angle as the base that is =5cm

According to the Pythagoras theorem,

√13)square -√5)square

=√13×13-5×5

=√169-25

=√144=12cm so the height is=12cm

put the formula,

=)1/2× b ×h=Area of a triangle

=)1/2×5×12

=)30cm

so, the area of a right angle triangle is 30cm

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