Question

2. Find the base of a triangle whose area is 0.48 dm2 and altitude is 8 cm.
and one side is 5 cm.​

Answer 1

Answer:

the base of a triangle (b)= 12 cm or 1.2 dm

Step-by-step explanation:

given ,

the altitude of a triangle (h) = 8 cm = 0.1* 8 dm = 0.8 dm and the area of a triangle = 0.48 dm2

to find ,the base of a triangle (b)= ?

we know that,

the area of a triangle = 1/2bh

= 1/2 * b* 0.8 = 0.48

= b * 0.4 = 0.48

= b = 48/0.4 = 1.2 dm

= b = 1.2 * 10 cm = 12cm ( since, 1 dm = 10 cm )

hence, the base of a triangle (b) = 12 cm or 1.2 dm

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